Two vessels contain milk and water in the ratio 3: 2 and 7: 3. Find the ratio in which the contents of the two vessels have to be mixed to get a new mixture in which the ratio of milk and water 2: 1. |
A) 2 : 1
B) 1 : 2
C) 4 : 1
D) 1 : 4
Correct Answer: B
Solution :
Given, ratio of milk and water in first vessel = 3 : 2 |
\[\therefore \] Part of milk in 1 st vessel \[=\frac{3}{5}\] \[\left[ by\frac{a}{a+b} \right]\] |
and ratio of milk and water in second vessel =7 : 3 |
\[\therefore \] Part of milk in second vessel \[=\frac{7}{10}\] |
and new mixture ratio = 2 : 1 |
By alligation rule |
\[\therefore \] Required ratio \[=\frac{1}{30}:\frac{1}{15}=1:2\] |
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