If radius of base of right circular cylinder is doubled and height becomes halted, then the ratio of new volume of cylinder to the volume of original cylinder is [SSC (CGL) 2012] |
A) 2 : 1
B) \[\pi :2\]
C) 1 : 2
D) \[2:\pi \]
Correct Answer: A
Solution :
\[\frac{\text{Volume}\,\text{of}\,\text{new}\,\text{cylinder}}{\text{Volume}\,\text{of}\,\text{original}\,\text{cylinder}}\] |
\[\text{=}\,\,\frac{\pi {{(2r)}^{2}}\left( \frac{h}{2} \right)}{\pi {{r}^{2}}h}\,\,=\,\,\frac{2{{r}^{2}}h}{{{r}^{2}}h}=2:1\] |
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