In the given figure, AOB is a straight line. If \[\angle AOC=40{}^\circ ,\]\[\angle COD=4x{}^\circ \]and \[\angle BOD=3x{}^\circ ,\] then \[\angle COD\] is equal to |
A) \[80{}^\circ \]
B) \[100{}^\circ \]
C) \[120{}^\circ \]
D) \[140{}^\circ \]
Correct Answer: A
Solution :
\[4x+3x+40=180\]\[\Rightarrow \,\]\[7x=180-40\] |
\[\Rightarrow \] \[7x=140\,\,\Rightarrow \,\,x=20{}^\circ \] |
\[\therefore \] \[4x=80{}^\circ \] |
\[\angle COD=4x=4\times 20=80{}^\circ \] |
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