Directions: In the following questions, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate answer. |
I. \[4{{x}^{2}}+17x+15=0\] |
II. \[3{{y}^{2}}+19y+28=0\] |
A) If \[x\ge y\]
B) If \[x\le y\]
C) If \[x>y\]
D) If \[x<y\]
E) If relationship between x and y cannot be established
Correct Answer: C
Solution :
I. \[4{{x}^{2}}+17x+15=0\] |
\[\Rightarrow \] \[4{{x}^{2}}+12x+5x+15=0\] |
\[\Rightarrow \] \[4x\,(x+3)+5\,(x+3)=0\] |
\[\Rightarrow \] \[x=-\,3,\]\[\frac{-\,5}{4}\] |
II. \[3{{y}^{2}}+19y+28=0\] |
\[\Rightarrow \] \[3{{y}^{2}}+12y+7y+28=0\] |
\[\Rightarrow \] \[3y\,(y+4)+7\,(y+4)=0\] |
\[\Rightarrow \] \[y=-\,4,\]\[\frac{-7}{3}\] |
\[\therefore \] \[x>y\] |
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