question_answer

In the given figure, ABCD is a parallelogram in which diagonals AC and BD intersect at O. If area of (parallelogram ABCD) is \[52\,c{{m}^{2}},\] then the area \[(\Delta OAB)\] is equal to

A) \[26\,c{{m}^{2}}\]                  

B) \[18.5\,c{{m}^{2}}\]

C) \[39\,c{{m}^{2}}\]                  

D) \[13\,c{{m}^{2}}\]

Correct Answer: D

Solution :

According to the question,

\[ar\,(\Delta OAB)=\frac{1}{4}ar\] (parallelogram ABCD)

\[=\frac{1}{4}\times 52=13\,\,c{{m}^{3}}\]