Directions: In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer. |
I. \[\frac{12\times 4}{{{x}^{4/7}}}-\frac{3\times 4}{{{x}^{4/7}}}={{x}^{10/7}}\] |
II. \[{{y}^{3}}+783=999\] |
A) If \[x>y\]
B) If \[x\ge y\]
C) If \[x<y\]
D) If \[x\le y\]
E) If \[x=y\] or the relationship cannot be established
Correct Answer: D
Solution :
I. \[\frac{12\times 4}{{{x}^{4/7}}}-\frac{3\times 4}{{{x}^{4/7}}}={{x}^{10/7}}\] |
\[\Rightarrow \] \[\frac{48-12}{{{x}^{4/7}}}={{x}^{10/7}}\] |
\[\Rightarrow \] \[36={{x}^{2}}\]\[\Rightarrow \]\[x=\pm \,\,6\] |
II.\[{{y}^{3}}=999-783=216\] |
\[\Rightarrow \] \[y=6\] |
\[\therefore \] \[x\le y\] |
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