A number was divided successively in order by 4, 5 and 6. The remainders were respectively 2, 3 and 4. The number is |
A) 214
B) 478
C) 954
D) 1908
Correct Answer: B
Solution :
LCM of 4, 5 and 6 = 60 |
Constant remainder \[=4-2=5-3\] |
\[=6-4=2\] |
\[\therefore \] Least number \[=60-2=58\] |
\[\therefore \] Number which is in the form of \[60K-2.\] |
But hit and trail K = 8 gives the required number. |
\[\therefore \] \[60K-2=60\times 8-2\] |
\[=480-2=478\] |
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