Two vessels A and B contain milk and water mixed in the ratio 8: 5 and 5: 2, respectively. The ratio in which these two mixtures be mixed to get a new mixture containing \[69\frac{3}{13}%\] milk is, |
A) 2 : 7
B) 3 : 5
C) 5 : 2
D) 5 : 7
Correct Answer: A
Solution :
Let cost of 1 L milk be Rs. 1. |
Milk in 1 L mixture in \[A=Rs.\frac{8}{13}L,\] |
CP of 1 L mixture in \[A=Rs.\,\frac{8}{13}\] |
Milk in 1 L mixture in \[B=\frac{5}{7}L,\] |
CP of 1 L mixture in \[B=Rs.\,\frac{5}{7}\] |
Milk in 1 L of final mixture |
\[=\left( \frac{900}{13}\times \frac{1}{100}\times 1 \right)=\frac{9}{13}L\] |
Mean price \[=Rs.\,\,\frac{9}{13}\] |
By the rule of alligation, we have |
\[\therefore \] Required ratio \[=\frac{2}{91}:\frac{1}{13}=2:7\] |
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