A basket contains three red and four green balls. If four balls are drawn at random from the basket, what is the probability that two are red and two are green? |
A) \[\frac{4}{7}\]
B) \[\frac{2}{7}\]
C) \[\frac{18}{35}\]
D) \[\frac{3}{14}\]
E) None of these
Correct Answer: C
Solution :
Required probability |
\[=\,\,\frac{{}^{3}{{C}_{2}}\times {}^{4}{{C}_{2}}}{{}^{7}{{C}_{4}}}=\frac{3\times 6}{7\times 5}=\frac{18}{35}\] |
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