A) 40
B) 38
C) 36
D) 39
Correct Answer: A
Solution :
As, P=16 and \[\begin{matrix} 20 & {} & 1 & {} & 16 & {} & {} \\ T & {} & A & {} & P & {} & {} \\ \downarrow & {} & \downarrow & {} & \downarrow & {} & {} \\ 20 & + & 1 & + & 16 & = & 37 \\ \end{matrix}\] Similarly, \[\begin{matrix} 3 & {} & 21 & {} & 16 & {} & {} \\ C & {} & U & {} & P & {} & {} \\ \downarrow & {} & \downarrow & {} & \downarrow & {} & {} \\ 3 & + & 21 & + & 16 & = & 40 \\ \end{matrix}\] \[\therefore \] \[CUP=40\]You need to login to perform this action.
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