A) 0
B) 2
C) 3
D) 4
Correct Answer: D
Solution :
Let us divide the different powers of 4 by 6 and find the remainder. So remainder for \[{{4}^{1}}=4,{{4}^{2}}=4,{{4}^{3}}=4,{{4}^{4}}=4,{{4}^{5}}=4,{{4}^{6}}=4\]and so on. Hence remainder for any power of 4 will be 4 only.You need to login to perform this action.
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