A) 24
B) 26
C) 42
D) 46
Correct Answer: A
Solution :
Let the ten digit be x. Then, unit's digit \[~=x+2\] Number \[=10x+(x+2)=11x+2;\] Sum of digits \[=x+(x+2)=2x+2\] \[\therefore \]\[(11x+2)(2x+2)=144\Rightarrow 22{{x}^{2}}+26x-140=0\] \[\Rightarrow \] \[(11x+35)\,(x-2)=0\Rightarrow x=2\] Hence, required number = 24.You need to login to perform this action.
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