A) 1.5%
B) 2.5%
C) 3.7%
D) 4.2%
E) 1.7%
Correct Answer: A
Solution :
\[SI=\frac{P\times R\times T}{100}\] Now,\[{{S}_{1}}-{{S}_{2}}=\frac{P\times {{R}_{1}}\times T}{100}-\frac{P\times {{R}_{2}}\times T}{100}\] or,\[150=\frac{PT}{100}({{R}_{1}}-{{R}_{2}})\] or,\[150=\frac{2500\times 4}{100}({{R}_{1}}-{{R}_{2}})\] \[\therefore \]\[{{R}_{1}}-{{R}_{2}}=\frac{150\times 100}{2500\times 4}=1.5%\]
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