A) 1
B) 3
C) 0
D) 21
Correct Answer: D
Solution :
[d] Here, \[\frac{6x-\,1}{x}+\frac{7y-\,1}{y}+\frac{8z-\,1}{z}=0\] Then, \[\frac{1}{x}+\frac{1}{y}+\frac{1}{z}=?\] Now, \[\Rightarrow \,\,\frac{6x}{x}-\,\frac{1}{x}+\frac{7y}{y}-\,\frac{1}{y}+\frac{8z}{z}-\,\frac{1}{z}=0\] \[\Rightarrow \,\,\,6-\,\frac{1}{x}+7-\,\frac{1}{y}+8-\,\frac{1}{z}\] \[\Rightarrow \,\,\,21-\,\left( \frac{1}{x}+\frac{1}{y}+\frac{1}{z} \right)=0\] \[\therefore \,\,\,\frac{1}{x}+\frac{1}{y}+\frac{1}{z}=21\]
You need to login to perform this action.
You will be redirected in
3 sec
