A) 2:1
B) 1:3
C) 1:1
D) 1:2
Correct Answer: C
Solution :
According to question, \[{{(x+y)}^{2}}=4xy\] \[\Rightarrow {{x}^{2}}+{{y}^{2}}+2xy-4xy=0\] \[\Rightarrow \,\,\,{{(x-\,y)}^{2}}=0\] \[\Rightarrow x=y\]You need to login to perform this action.
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