A) \[\frac{3}{7}\]
B) \[1\frac{1}{7}\]
C) 1
D) 2
Correct Answer: C
Solution :
[c] \[\frac{4}{7}+\frac{\frac{2y}{y}-\frac{x}{y}}{\frac{2y}{y}+\frac{x}{y}}=\frac{4}{7}+\frac{2-\frac{4}{5}}{2+\frac{4}{5}}=\frac{4}{7}+\frac{6}{14}=1\]You need to login to perform this action.
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