question_answer

Direction: In these questions, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate option. Give answer

I.\[3{{x}^{2}}+13x+14=0\]

II.\[4{{y}^{2}}-28y+13=0\]

A)  if\[x>y\]                      

B)  if\[x\ge y\]        

C)         if\[x<y\]          

D)         if\[x\le y\]

E)  if \[x=y\] or relationship between \[x\] and \[y\] can't be established.

Correct Answer: C

Solution :

I. Step II.\[+\frac{7}{3}\]                       \[+\frac{6}{3}\] Step III.\[x=-\frac{7}{3},\,\,-2\] II. Step II.\[-\frac{26}{4}\]                       \[-\frac{2}{4}\] Step III.\[y=+\frac{13}{2},\,\,+\frac{1}{2}\] Hence \[x<y\]