| Direction: Each question consists of two conclusions followed by five groups of statements. Consider the given conclusions to be true even if they seem to be at variance with commonly known facts. Read the conclusions and then decide from which group of the statements the conclusions can be drawn. |
| Conclusions: I All MCAs can be M Techs. |
| II Some B Techs not being MBAs is a possibility. |
A)
Statements: All B Techs are MBAs. Some B Techs are MCAs. No MBA is an M Tech.
B)
Statements: All MCAs are M Techs. Some M Techs are B Techs. All B Techs are MBAs.
C)
Statements: All B Techs are M Techs. Some M Techs are MBAs. No MBA is an MCA.
D)
Statements: All MBAs are MCAs. No MCA is an M Tech. No M Tech is a B Tech.
E)
Statements: All MCAs are MBAs. No MBA is an M Tech. No M Tech is a B Tech.
Correct Answer: C
Solution :
Check options one by one: (A) All B Techs are MBAs (A) + No MBA is an M Tech (E) = A + E = E = No B Tech is an M Tech (E) \[\to \]conversion \[\to \] No M Tech is a B Tech (E) + Some B Techs are MCAs (I) = E + I = O* = Some MCAs are not M Techs (I). Hence conclusion I does not follow. And conclusion II also does not follow from first statement. Hence (A) does not follow. (B) Conclusion I follows from first statement. But conclusion II does not follows from third statement. Hence (B) does not follow. (C) All B Techs are M Techs (A) + Some M Techs are MBAs (A) = A + 1 = No conclusion. But the possibility in II exists. Hence conclusion II follows. Again, Some M Techs are MBAs (I) + No MBA is an MCA (E) = I + E = O = Some M Techs are not MCAs (O). Hence the possibility in I exists. Thus, conclusion 1 also follows. So, option (C) is valid. (D) From second statement conclusion I does not follow. (E) All MCAs are MBAs (A) + No MBA is an M Tech (E) = A + E = E = No MCA is an M Tech. Hence conclusion I docs not follow.
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