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Railways Sample Paper RRBs Assistant Loco Pilot and Technician CBT STAGE-I Sample Paper-27

  • question_answer
    If \[\sin A:\cos A=4:7,\] then \[\frac{7\sin A-3\cos A}{7\sin A+2\cos A}\] is equal to

    A)  \[\frac{1}{6}\] 

    B)  \[\frac{1}{3}\]

    C)  \[\frac{3}{14}\]            

    D)  \[\frac{3}{2}\]

    Correct Answer: A

    Solution :

    Let sin A = 4 k and cos A = 7 k. Then, \[\frac{7\sin A-3\cos A}{7\sin A+2\cos A}\] \[=\frac{7\times 4k-3\times 7k}{7\times 4k+2\times 7k}\] \[=\frac{28k-21k}{28k+14k}\] \[=\frac{7k}{24k}=\frac{1}{6}\]


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