A) 0
B) 1
C) 2
D) \[4\sin \theta \cos \theta \]
Correct Answer: C
Solution :
Using \[{{(a-b)}^{2}}+{{(a+b)}^{2}}\] \[=2({{a}^{2}}+{{b}^{2}}),\] we have \[{{(\cos \theta -\sin \theta )}^{2}}+{{(\cos \theta +\sin \theta )}^{2}}\] \[=2({{\cos }^{2}}\theta +{{\sin }^{2}}\theta )=2\times 1=2\]You need to login to perform this action.
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