Answer:
Given 
in which 
(1/2)
To prove
(1/2)
Construction Draw the bisector 
of 
which meets in D.
(1/2)
Proof In 
and 
we have
[given](1/2)
[by construction]
(1/2)
[by SAS congruence]
[by CPCT](1)
Hence proved.
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