and 
respectively.
They collide and after the collision, the first object moves at a velocity of 
Determine
the velocity of the second object.
Or
(i) Explain why is it difficult
to walk on sand?
(ii) Why is the recoil of a
heavy gun, on firing, not so strong as that of a light gun using the same
cartridge?
(iii) A constant force acts on
an object of 5 kg for a period of 2 s. It increases the velocity of an object
from 3 m/s to 7 m/s. Find the magnitude of the applied force. Now if the force
was applied for a period of 5 s, what would be the final velocity of the
object?
Answer:
Before collision,
and 
After
collision, m; =100 g = 0.1 kg
(1)
Let
velocity of second object after collision be
Since, there
is no external force on the system.
So,
total momentum before collision = total momentum after collision
(2)
Or
(i)
While walking on sand, the sand gets pressed down, impacting less reaction
force on the person. (1)
(ii)
The mass of the gun is higher. So, it recoils velocity is
less. (1)
(iii)
Given,
(1/2)
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