Experiment | time | Total pressure (atm) |
I II | 0 100 | 0.5 0.6 |
Answer:
+
Initial at a 0 0
T = 0 time (a - x) x x
[1]
Initial pressure is due to atm
At time t (100 s) pressure is due to and
Thus,
x = 0.6 - 0.5
= 0.1 atm [1]
(a - x) 0.5 - 0.
1 = 0.4 atm
Thus,
[2]
Or
(a)
[1]
(b)(half-life
period) = 3 hrs
After 8 hrs
[3]
(c) Coordinates involve In [R] terms.
Thus it may be first order reaction.
(i) Order =1
(ii) Unit of rate constant=time-1
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