A) \[\frac{3}{182}\]
B) \[\frac{5}{182}\]
C) \[\frac{5}{12}\]
D) \[\frac{1}{4}\]
E) \[\frac{1}{8}\]
Correct Answer: B
Solution :
Total number of balls in the bag =3+5+6 = 14 Total possible outcomes = Selection of 3 balls out of 14 balls \[{{=}^{14}}{{C}_{3}}=\frac{14\times 13\times 12}{1\times 2\times 3}=364\] Total favourable outcomes = Selection of 3 balls out of 5 blue balls \[{{=}^{5}}{{C}_{3}}=\frac{5\times 4\times 3}{1\times 2\times 3}=10\] \[\therefore \]Required probability \[=\frac{10}{364}=\frac{5}{182}\]
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