A) \[8\frac{8}{9}\]
B) \[9\frac{1}{3}\]
C) \[8\frac{5}{8}\]
D) \[10\frac{2}{9}\]
E) \[9\frac{1}{6}\]
Correct Answer: A
Solution :
Time taken by A alone = 24 days According to the question, Time taken by B alone \[=\frac{100}{120}\times 24=20\,days\] Time taken by C alone \[=\frac{100}{125}\times 20=16\,days\] \[\therefore \,\,\] (B + C)'s 1 day's work \[=\frac{1}{20}+\frac{1}{16}\] \[=\frac{4+5}{80}=\frac{9}{80}\] \[\therefore \] Required time \[\,=\frac{80}{9}\] \[=8\frac{8}{9}\] days
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