A) 450
B) 200
C) 300
D) Cannot be determined
E) None of these
Correct Answer: E
Solution :
Let the length of the platform be 2x metre. Speed of train = 90 kmph \[=\left( \frac{90\times 5}{18} \right)\] m / sec = 25 m/sec. Again, Speed of train \[=\frac{Lengh\text{ }of\text{ }\left( platform\text{ }+\text{ }train \right)}{Time\text{ }taken\text{ }in\text{ }crossing}\] \[\Rightarrow 25=\frac{2x+x}{36}\] \[\Rightarrow 3x=25\times 36\] \[\therefore x=\frac{25\times 36}{3}=300\] \[\therefore \] Length of platform = 2x = 600 metre
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