| 4095 | 4224 | 4355 | ? | 4623 | 4760 |
A) 4487
B) 4395
C) 4478
D) 4398
E) 4488
Correct Answer: E
Solution :
The series is \[{{\left( 64 \right)}^{2}}-1,\text{ }{{\left( 65 \right)}^{2}}-1,\] \[{{\left( \text{66} \right)}^{\text{2}}}\text{-1, }{{\left( \text{67} \right)}^{\text{2}}}\text{-1, }{{\left( \text{68} \right)}^{\text{2}}}\text{-1, }{{\left( \text{69} \right)}^{\text{2}}}\text{-1, }...\] ie \[{{\left( \text{64} \right)}^{\text{2}}}\text{-1=4095, }{{\left( \text{65} \right)}^{\text{2}}}\text{-1=4224,}\] \[{{\left( \text{66} \right)}^{\text{2}}}\text{-1=4355, }{{\left( \text{67} \right)}^{\text{2}}}\text{-1=}\mathbf{4488}\text{,}\] \[{{\left( \text{68} \right)}^{\text{2}}}\text{-1=4623, }{{\left( \text{69} \right)}^{\text{2}}}\text{-1=4760, }...\]
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