A) \[\frac{1}{6}\]
B) \[\frac{5}{12}\]
C) \[\frac{1}{2}\]
D) \[\frac{7}{9}\]
E) \[\frac{8}{15}\]
Correct Answer: B
Solution :
\[n(S)=6\times 6=36\] E=event that the sum is a prime number \[=\{(1,1)(1,2),(1,4),(1,6),(2,1),(2,3),(2,5),\] \[(3,1),(3,4),(4,1),(4,3),(5,2),(5,6),(6,1),(6,5)\}\] \[\therefore \]\[n(E)=15,\] \[\therefore \]\[P(E)=\frac{n(E)}{n(S)}=\frac{15}{36}=\frac{5}{12}\]
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