Banking Sample Paper SBI PO (Main) Sample Test Paper-9

  • question_answer

    Direction: Study the bar-graph and pie- chart to answer the question based on it.
    The bar graph shows the no. of copies of newspapers sold (in lakh) by six different companies and the pie-chart shows the revenue generated by six companies in 2013.
    Company
    Total revenue generated =Rs. 36 crore
     

    The circumference of a circle is equal to average revenue generated by all companies taken together. What would be the area of that circle? (Note: Neglect the crore part of revenue in calculation)

    A) \[\frac{\text{64}}{\text{31}}\,\text{uni}{{\text{t}}^{\text{2}}}\]           

    B) \[\frac{\text{67}}{\text{32}}\,\text{uni}{{\text{t}}^{\text{2}}}\]

    C) \[\frac{\text{63}}{22}\,\text{uni}{{\text{t}}^{\text{2}}}\]                     

    D)  \[\frac{44}{23}\,\text{uni}{{\text{t}}^{\text{2}}}\]

    E)  None of these

    Correct Answer: C

    Solution :

     Average revenue \[=\frac{36}{6}=6\]crore Now, \[2\pi r=6\] \[\therefore \]\[r=\frac{6}{2\pi }=\frac{3}{\pi }\] Now, area of the circle \[=\pi \times {{r}^{2}}\] \[=\pi \times \frac{3}{\pi }\times \frac{3}{\pi }=\frac{9}{\pi }\,\text{uni}{{\text{t}}^{\text{2}}}\]\[=\frac{9}{22}\times 7=\frac{63}{22}\,\text{uni}{{\text{t}}^{\text{2}}}\]


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