A) 180
B) 1550
C) 6995
D) 99090
Correct Answer: D
Solution :
According to the question, First number = a = 103 Last number = l = 998 \[\therefore \] If the number of such numbers be n, then, \[998=103+(n-1)\times 5\] \[\Rightarrow \] \[(n-1)\times 5=998-103=895\] \[\Rightarrow \] \[n-1=\frac{895}{5}=179\] \[\Rightarrow \] \[n=180\] \[\therefore \] \[S=\frac{n}{2}(a+l)\] \[=\frac{180}{2}(103+998)\] \[=90\times 1101=99090\]You need to login to perform this action.
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