A) 2
B) \[\sqrt{3}\]
C) \[\sqrt{2}\]
D) 3
Correct Answer: C
Solution :
\[\sqrt{12}+\sqrt{18}\] \[=\sqrt{3\times 2\times 2}+\sqrt{2\times 3\times 3}\] \[=2\sqrt{3}+3\sqrt{2}\] \[\therefore \] Required difference \[=2\sqrt{3}+3\sqrt{2}-2\sqrt{3}-2\sqrt{2}=\sqrt{2}\]You need to login to perform this action.
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