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SSC Sample Paper SSC CGL - Sample Paper-14

  • question_answer
    What least number must be subtracted from 1936 so that the resulting number when divided by 9, 10 and 15 will leave in each case the same remainder 7?

    A) 37                                

    B) 36

    C) 39                    

    D) 30

    Correct Answer: C

    Solution :

    LCM of 9, 10 and 15 = 90. The multiple of 90 are also divisible by 9, 10 or 15. \[\therefore \]      \[21\times 90=1890\] will be divisible by them. \[\therefore \] Now, 1897 will be the number that will give remainder 7. \[1936-1897\] Required number = \[1936-1897\]   = 39  


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