A) 6
B) 10
C) 12
D) 14
Correct Answer: A
Solution :
Let the numerator = x and denominator = y \[\therefore \] Fraction \[=\frac{x}{y}\] and \[\frac{x}{y+1}=\frac{1}{2}\] \[\Rightarrow \] \[2x=y+1\] \[\Rightarrow \] \[x=\frac{y+1}{2}\] \[\frac{x+1}{y}=1\] \[\Rightarrow \] \[x+1=y\] \[\Rightarrow \] \[\frac{y+1}{2}+1=y\] \[\Rightarrow \] \[\frac{y+1+2}{2}=y\] \[\Rightarrow \] \[y+3=2y\] \[\Rightarrow \] \[y=2\] \[x+1=3\] \[\Rightarrow \] \[x=2\] \[xy=2\times 3=6\]
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