A) Monday
B) Tuesday
C) Wednesday
D) Saturday
Correct Answer: C
Solution :
22nd January, 2003 = (2002yr + Period from 1.1.2003 to 22.1.2003) 2000 yr = 0 odd days 2 yr == 2 ordinary years = 2 odd day Jan 22 = (3 weeks + 1 day) = 1 odd day Total number of odd days = (0 + 2 + 1) days = 3 days So, 22n January, 2003 was Wednesday.You need to login to perform this action.
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