A) 500
B) 600
C) 750
D) 900
Correct Answer: C
Solution :
Let the length of a train = x m \[\therefore \] Length of platform = x m \[\therefore \] \[\frac{90\times 5}{18}=\frac{x+x}{60}\] \[\Rightarrow \] \[2x=25\times 60\] = 1500 \[\Rightarrow \] \[x=750\,m\]You need to login to perform this action.
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