A) 75 dm
B) 18 dm
C) 6 dm
D) 2 dm
Correct Answer: B
Solution :
Let the length of tank \[=x\,dm\] Depth \[=\frac{x}{3}\,dm\] Breadth \[=\left( x-\frac{x}{3} \right)\times \frac{1}{3}\times \frac{1}{2}\] \[=\frac{2x}{3}\times \frac{1}{3}\times \frac{1}{2}=\frac{x}{9}\,dm\] Volume of tank \[=x\times \frac{x}{9}\times \frac{x}{3}=\frac{{{x}^{3}}}{27}\] According to the question, \[\frac{{{x}^{3}}}{27}=216\] \[\Rightarrow \] \[{{x}^{3}}=27\times 216\] \[\Rightarrow \] \[x={{(27\times 216)}^{1/3}}\] \[\Rightarrow \] \[3\times 6=18\,\,dm\]
You need to login to perform this action.
You will be redirected in
3 sec
