SSC Sample Paper SSC CGL - Sample Paper-1

  • question_answer
    When the circumference of a toy ballon is increased from 20 cm to 25 cm, its radius (in cm) is increased by

    A)  5                                

    B)  \[\frac{5}{\pi }\]         

    C)  \[\frac{5}{2\pi }\]                     

    D)  \[\frac{\pi }{5}\]

    Correct Answer: C

    Solution :

    Here, we can treat the balloon as sphere. Its circumference \[=2\pi r\] \[\therefore \]      \[2\pi {{r}_{1}}=20\]             \[2\pi {{r}_{2}}=25\] On dividing Eq. (ii) by Eq. (i), \[\Rightarrow \]   \[\frac{2\pi {{r}_{2}}}{2\pi {{r}_{1}}}=\frac{25}{20}\] \[\Rightarrow \] \[\frac{{{r}_{2}}}{{{r}_{1}}}=\frac{5}{4}\] \[\therefore \] Increase \[{{r}_{2}}-{{r}_{1}}\]             \[=\frac{5}{4}{{r}_{1}}-{{r}_{1}}=\frac{1}{4}{{r}_{1}}=\frac{1}{4}\times \frac{20}{2\pi }\]             \[=\frac{5}{2\pi }\]       


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