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SSC Sample Paper SSC CGL - Sample Paper-20

  • question_answer
    The perimeter of a rectangle is 160 m and the difference of two sides is 48 m. Find the side of a square whose area is equal to the area of this rectangle.

    A) 32 m

    B) 8 m

    C) 4 m                              

    D) 16 m

    Correct Answer: A

    Solution :

    Let the length and breadth of rectangle are a and b respectively. According to the question,             \[2(a+b)=160\] \[\Rightarrow \]   \[a+b=80\]                                ?(i) \[\Rightarrow \]   \[\frac{a-b=48}{2a=128}\]                                 ?(ii) \[\Rightarrow \]   \[a=\frac{128}{2}=64\,m\] From Eq. (i),             \[b=80-64=16m\] \[\therefore \] Area of rectangle \[=64\times 16\,{{m}^{2}}\] \[\Rightarrow \]   \[{{(Side)}^{2}}=64\times 16\] \[\Rightarrow \]   \[Side=8\times 4=32\,m\]                       


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