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SSC Sample Paper SSC CGL - Sample Paper-20

  • question_answer
    \[\frac{9}{20}-\left[ \frac{1}{5}+\left\{ \frac{1}{4}+\left( \frac{5}{6}-\overline{\frac{1}{3}+\frac{1}{2}} \right) \right\} \right]\] is equal to

    A) 0         

    B) 1

    C) \[\frac{9}{20}\]                         

    D) \[\frac{9}{10}\]

    Correct Answer: A

    Solution :

    \[\frac{9}{20}-\left[ \frac{1}{5}+\left\{ \frac{1}{4}+\left( \frac{5}{6}-\overline{\frac{1}{3}+\frac{1}{2}} \right) \right\} \right]\] \[=\frac{9}{20}-\left[ \frac{1}{5}+\left\{ \frac{1}{4}+\left( \frac{5}{6}-\frac{5}{6} \right) \right\} \right]\] \[=\frac{9}{20}-\left[ \frac{1}{5}+\frac{1}{4} \right]=\frac{9}{20}-\frac{9}{20}=0\]                   


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