A) 18, 12, 30
B) 24, 16, 40
C) 15, 10, 25
D) 21, 14, 35
Correct Answer: D
Solution :
Let the numbers be 3x, 2x and 5x. \[\therefore \] \[{{(3x)}^{2}}+{{(2x)}^{2}}+{{(5x)}^{2}}=1862\] \[\Rightarrow \] \[9{{x}^{2}}+4{{x}^{2}}+25{{x}^{2}}=1862\] \[\Rightarrow \] \[{{x}^{2}}=\frac{1862}{38}=49\] \[\Rightarrow \] \[x=7\] Hence, numbers are \[3\times 7,\] \[2\times 7\] and \[5\times 7\] i.e. 21, 14 and 35.
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