A) 10 m
B) 11 m
C) 11.2 m
D) 11.5 m
Correct Answer: C
Solution :
\[\therefore \] \[r=10\,m,\] \[h=14\,m\] \[\therefore \] Volume of earth dug out \[=\pi {{(10)}^{2}}\times 14\] \[=\frac{22}{7}\times 100\times 19=4400\,c{{m}^{3}}\] Let the height of cuboid \[=x\,cm\] \[\therefore \] \[\pi ({{15}^{2}}-{{10}^{2)}}\times x=4400\] \[\Rightarrow \] \[\frac{22}{7}(125-100)\times x=4400\] \[\Rightarrow \] \[x=\frac{7\times 4400}{22\times 125}=11.2\,m\]
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