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SSC Sample Paper SSC CGL - Sample Paper-26

  • question_answer
    How much pure alcohol has to be added to 400 mL of a solutions containing 15% of alcohol to change the concentration of alcohol in tne mixture of 32%?

    A) 60 mL              

    B) 100 mL

    C) 128 mL            

    D) 68 mL

    Correct Answer: B

    Solution :

    Quantity of alcohol in mixture \[=15%\,\,\text{of}\,\,400\]             \[\frac{15\times 400}{100}\] \[=60\,mL\] Let x mL of alcohol should be added to the mixture             \[\frac{60+x}{400+x}=\frac{32}{100}\] \[\Rightarrow \]   \[25(60+x)=8(400+x)\] \[\Rightarrow \]   \[17x=1700\] \[\Rightarrow \]   \[x=100\] \[\therefore \] 100 mL of alcohol should be added to the mixture.


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