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SSC Sample Paper SSC CGL - Sample Paper-26

  • question_answer
    P and Q can do a job in 2 days; Q and R can do it in 4 days and P and R in 12/5 days. What is the number of days required for P alone to do the job?

    A) 5/2                               

    B) 3

    C) 14/5                             

    D) 6

    Correct Answer: B

    Solution :

    One day work of Ps and Q?s \[=\frac{1}{2}\]                    ...(i) One day work of Q's and R?s \[=\frac{1}{4}\]        ... (ii) One day work of P's and R?s \[=\frac{5}{12}\]      ?(iii) On adding Eqs. (i), (u) and (iii), we get             \[2(P+Q+R)=\frac{1}{2}+\frac{1}{4}+\frac{5}{12}\] \[\Rightarrow \]   \[2(P+Q+R)=\frac{14}{12}\] \[\Rightarrow \]   \[P+Q+R=\frac{7}{12}\] On subtracting Eq. (ii) from Eq. (iv), we get             \[P=\frac{7}{12}-\frac{1}{4}\] \[\Rightarrow \]   \[P=\frac{1}{3}\] Hence, P's can do alone in 3 days.


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