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SSC Sample Paper SSC CGL - Sample Paper-30

  • question_answer
    Two persons P and Q start at the same time from city A for city B, 60 km away. P travels 4 km/h slower than Q. Q reaches city B and at once turns back meeting P, 12 km from city B. What is the speed of P?

    A) 8 km/h 

    B) 12 km/h

    C) 16 km/h            

    D) 20 km/h

    Correct Answer: A

    Solution :

    Distance travelled by P till they meet \[=60-12=48\,km\] Time taken by P till they meet \[=\frac{48}{x-4}\] Since, time taken by both will be equal. \[\therefore \]      \[\frac{72}{x}=\frac{48}{x-4}\] \[\Rightarrow \]   \[72x-288=48x\] \[\Rightarrow \]   \[24x=288\] \[\Rightarrow \] \[x=12\,\text{km/h}\] Speed of\[P=x-4\] \[=12-4=8\,\text{km/h}\]           


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