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SSC Sample Paper SSC CGL - Sample Paper-5

  • question_answer
    The length of rectangle is three times of its width. If the length of the diagonal is \[8\sqrt{10}\,\,cm,\] then the perimeter of the rectangle is

    A)  \[24\sqrt{10}\,\,cm\]                 

    B)  \[16\sqrt{10}\,\,cm\]

    C)  64 cm 

    D)  \[15\sqrt{10}\,\,cm\]

    Correct Answer: C

    Solution :

    Let the width of rectangle = x cm \[\therefore \] Length of rectangle = 3x cm \[\therefore \]      \[8\sqrt{10}=\sqrt{(9+1){{x}^{2}}}\] \[\Rightarrow \]   \[x=8\,cm\] \[\therefore \] Length of rectangle \[=24\,cm\] and breadth of rectangle \[=8\,cm\] \[\therefore \] Perimeter of rectangle \[=2(24+8)=64\,cm\]  


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