A) 2 : 1
B) 2 : 3
C) 3 : 2
D) 1 : 2
Correct Answer: A
Solution :
Weight of copper in 17 kg 500 g i.e., 17500 g of alloy \[=\frac{5}{7}\times 17500=12500\,g\] Weight of zinc\[=(17500-12500)\] = 5000 g 1250 g of zinc is mixed in alloy. \[\therefore \] Total weight of zinc \[=1250+5000=6250\text{ }g\] \[\therefore \] Required ratio \[=12500:6250=2:1\]You need to login to perform this action.
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