SSC Sample Paper SSC-CGL TIER - I Sample Test Paper-2

  • question_answer
    If \[0{}^\circ <~\theta <90{}^\circ \] and \[2{{\sin }^{2}}\theta +3\cos \theta =3\] then the value of \[\theta \] is:

    A)  \[30{}^\circ \]             

    B)  \[60{}^\circ \]

    C) \[45{}^\circ \]              

    D) \[75{}^\circ \]

    Correct Answer: B

    Solution :

     \[2{{\sin }^{2}}\theta +3\cos \theta =3\] \[\Rightarrow \]\[2(1-{{\cos }^{2}}\theta )+3\cos \theta =3\] \[\Rightarrow \]\[-2{{\cos }^{2}}\theta +3\cos -1=0\] \[\Rightarrow \]\[2{{\cos }^{2}}\theta -3\cos +1=0\] \[\Rightarrow \]\[2{{\cos }^{2}}\theta -2\cos \theta -\cos \theta +1=0\] \[\Rightarrow \]\[\,\,(2\cos \theta -1)(\cos \theta -1)=0\] \[\therefore \,\,\,\,\,\,\,\,\cos \theta =\frac{1}{2},0\,\,\,\,\,\,\,\,\,\,\,\,\therefore \,\,\]


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