SSC Sample Paper SSC-CGL TIER - I Sample Test Paper-6

  • question_answer
    In the given figure OS is on PQ. OR and OT are the bisector of \[\angle POS\]and\[\angle SOQ\]. If \[\angle POS\]= x then find\[\angle SOQ\].

    A) \[90{}^\circ -x\]                       

    B) \[80{}^\circ -\angle POR\]

    C) \[180{}^\circ -2\angle POR\]      

    D) \[90{}^\circ -\angle POR\]

    Correct Answer: C

    Solution :

    OS is on POQ So, \[\angle POS+\angle SOQ=180{}^\circ \text{ }but\angle POS=x\] \[x+\angle SOQ\text{ }=180{}^\circ ~\Rightarrow \angle SOQ=180{}^\circ -x\] \[=180{}^\circ -2\angle POR\](OR is bisector of)


You need to login to perform this action.
You will be redirected in 3 sec spinner