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SSC Sample Paper SSC-CGL TIER - I Sample Test Paper-8

  • question_answer
    If \[{{x}^{2}}=6+\sqrt{6+\sqrt{6+\sqrt{6+...\infty }}}\]then what is one of the values of x equal to?

    A) 6                                 

    B) 5

    C) 4                                 

    D) 3

    Correct Answer: D

    Solution :

    Here, \[{{x}^{2}}=6+\sqrt{6+\sqrt{6+\sqrt{6+...\infty }}}\] So, \[{{x}^{2}}=6+\sqrt{{{x}^{2}}}\Rightarrow {{x}^{2}}=6+x\] \[\Rightarrow {{x}^{2}}-x-6=0\Rightarrow {{x}^{2}}+2x-3x-6=0\] \[\Rightarrow \,x(x+2)-3(x+2)=0\] \[\Rightarrow \,(x-3)(x+2)=0\therefore x=\]


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