2. Sample Papers
  3. SSC

SSC Sample Paper SSC CHSL (10+2) Sample Test Paper-10

  • question_answer
    AB and CD are two parallel lines The points B and C are joined such that \[\angle \]ABC = \[65{}^\circ \],A line CE is drawn making angle of \[35{}^\circ \]with the line CB, EF is drawn parallel to AB.as show in figure then \[\angle \]CEF is equal to:

    A) \[160{}^\circ \]

    B) \[155{}^\circ \]

    C) \[150{}^\circ \]

    D) \[145{}^\circ \]

    Correct Answer: C

    Solution :

    \[\angle ABC=\angle BCD\,\,as\,\,AB||\,CD\] \[\angle BCD=65{}^\circ \] \[\angle ECD=65{}^\circ -\angle BCE\] \[=65{}^\circ -350=30{}^\circ \] \[\angle CEF+\angle ECD=180{}^\circ \] \[~\angle CEF=180{}^\circ -30{}^\circ =150{}^\circ \]


You need to login to perform this action.
You will be redirected in 3 sec spinner